x^2=5+4x-20

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Solution for x^2=5+4x-20 equation: 



x^2=5+4x-20

We move all terms to the left:

x^2-(5+4x-20)=0

We add all the numbers together, and all the variables

x^2-(4x-15)=0

We get rid of parentheses

x^2-4x+15=0

a = 1; b = -4; c = +15;
Δ = b2-4ac
Δ = -42-4·1·15
Δ = -44
Delta is less than zero, so there is no solution for the equation

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